Thus there are 5 X 473 grams in the bottle, 2365 grams Divide this weight by the molecular weight of acetic acid (grams/mole) to get the answer MW = 60;Use the number of moles calculated in Step 2 and the molar mass of sucrose from Step 3 to solve for grams 002 mol of C 12 H 22 O 11 × g C 12 H 22 O 11 / 1 mol C 12 H 22 O 11 = 685 g C 12 H 22 O 11Using the values above, if titration requires 102 mmol of NaOH to reach the endpoint, the sample must also contain 102 mmol of acetic acid If the volume of the vinegar used is 805 mL, the molarity of acetic acid is 102 mmol / 805 mL = 0127 M In this experiment, a carefully measured volume of vinegar (V analyte) is placed into a beaker and the mass determined
Pdf Effect Of Recycled Content And Rpet Quality On The Properties Of Pet Bottles Part I Optical And Mechanical Properties
In question 28 one of the four bottles containing 2 moles